If the maximum speed of the elevator is 1.30 m/s and it takes a total of 3.00 s for the elevator to move between the floors, what is the distance between the floors if the time that the elevator is at its top speed is 2.52 s ?

Answer 1

During the time the elevator is traveling at maximum speed, it travels 1.30 m/s*2.52 s = 3.28 m. During the remaining 0.48 s of the 3 sec interval, its average speed is 0.65 s and it travels 0.65* 0.48 = 0.31 m
Add the two times for the total distance between floors.