For earth, g = GMm/r^2 = 9.8
For planet x, we have
GM(.571m)/(.787r)^2 = GMm/r^2 * .571/.787^2 = .922g = ?
If the mass of a planet is 0.571 times that of the Earth and its radius is 0.787 times that of the Earth, estimate the gravitational field g at the surface of the planet. The gravitational acceleration on Earth is 9.8 m/s2.
Answer in units of m/s2
2 answers
9.8m/s2