If the length of a rectangle is decreased by 4 cm and the width is increased by 5 cm, the result will be a square, the area of which will be 40 cm2 greater than the area of the rectangle. Find the area of the rectangle.

Answer 1

If the rectangle has length x and width y, and the square has side s, then
s = x-4 = y+5
so, y=x-9

s^2 = xy+40
(x-4)^2 = x(x-9)+40
find x, and then just finish up.

xy

Answer 2

This wasn't any help. Give me the answer