Asked by Sam
If the length of a rectangle is decreased by 4 cm and the width is increased by 5 cm, the result will be a square, the area of which will be 40 cm2 greater than the area of the rectangle. Find the area of the rectangle.
Answers
Answered by
Steve
If the rectangle has length x and width y, and the square has side s, then
s = x-4 = y+5
so, y=x-9
s^2 = xy+40
(x-4)^2 = x(x-9)+40
find x, and then just finish up.
xy
s = x-4 = y+5
so, y=x-9
s^2 = xy+40
(x-4)^2 = x(x-9)+40
find x, and then just finish up.
xy
Answered by
Ann Buolion
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