If the length of a rectangle in terms of x is 4x^2+9x+12 , and its width is 2x + 8, what is the perimeter of this rectangle?

Answer 1

To find the perimeter of a rectangle, you add up all the sides.

Given that the length of the rectangle is 4x^2 + 9x + 12 and the width is 2x + 8, the perimeter can be calculated as follows:

Perimeter = 2*(length + width)
Perimeter = 2*(4x^2 + 9x + 12 + 2x + 8)
Perimeter = 2*(4x^2 + 11x + 20)

Now, we can simplify this expression:

Perimeter = 8x^2 + 22x + 40

Therefore, the perimeter of the rectangle is 8x^2 + 22x + 40.