If the length of a rectangle in terms of x

Question

is 3x2 +7x +9
, and its width is 3x +6
, what is the perimeter of this rectangle?

Answer 1

To find the perimeter of a rectangle, we add up the lengths of all four sides.

In this case, the length is 3x^2 + 7x + 9 and the width is 3x + 6.

So the two lengths would add up to:

(3x^2 + 7x + 9) + (3x^2 + 7x + 9)

Simplifying this expression, we get:

6x^2 + 14x + 18

And the two widths would add up to:

(3x + 6) + (3x + 6)

Simplifying, we get:

6x + 12

Now we can add up all four sides:

Perimeter = (6x^2 + 14x + 18) + (6x + 12)

Simplifying and combining like terms, we get:

Perimeter = 6x^2 + 20x + 30

So the perimeter of the rectangle in terms of x is 6x^2 + 20x + 30.