If the Kb of a weak base is 2.6 × 10-6, what is the pH of a 0.24 M solution of this base?

Answer 1

Call the weak base ANH2
........ANH2 + HOH ==> ANH3^+ + OH^-
I.......0.24.............0........0
C.........-x.............x........x
E......0.24-x............x.........x

Kb = (ANH3^+()(OH^-)/(ANH2)
Substitute from the ICE chart and solve for x = (OH^-) and convert to pH.