If the integral of 9x-2 /(x-3)(2x-1)dx= (A)Ln|x – 3| + (B)Ln|2x – 1| + constant, then what is the value of A – B?

a. 3
b. 4.5
c. 5.5
d. 4

3 answers

I get 5.5
What do you get?
I don't see a choice for you answer to this "partial fractions" question.
To check if you have the correct values of A and B,
evaluate a(2x-1) + B(x-3)
you should get 9x - 2
Then simply find A-B

btw, I did not get any of the given choices.

Let me know what you found for A and B
A(2x-1) + B(x-3) = 9x - 2
let x = 3, 5A + 0 = 25 ----> A = 5
let x = 1/2
0 - (5/2)B = 5/2 -----> B = -1
A - B = 5 - (-1) = 6
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