really?
Let u = 5-x
so du = -dx
∫f(5-x) dx = -∫f(x) dx
that "5-" just shifts and reflects the curve. It does not change the area.
If the integral from 1 to 4 of f(x)dx = 6, what is the value of the integral from 1 to 4 of f(5-x)dx?
a. -6
b. -1
c. 0
d. 3
e. 6
no idea how to do this
1 answer