............2HD ==> H2 + D2
initial.....2.270...0.....0
change......-2p.....p.....p
equil.....2.27-2p...p.....p
Substitute into Kp equation and solve for p. Then %decomp = (p/2.27)*100 = ?
If the initial pressure of HD(g) is 2.270 atm, calculate the % decomposition of HD(g) when the reaction comes to equilibrium according to the balanced equation. The value of Kp at 727.0 °C is 0.26. The initial pressure of the reaction products is 0 atm.
2HD(g) = H2(g)+D2(g)
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