If the gravitational force between two objects of masses 10kg each is 50N. What will be the new gravitational force if the distance between the objects is reduced to 1/3rd of the original distance and the mass of one object is doubled?

1 answer

The gravitational force between two objects is given by the equation F = (G * m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the objects.

In this case, we are given:
m1 = m2 = 10 kg (mass of each object)
F = 50 N (gravitational force)
r = original distance between the objects

To find the new gravitational force, we need to determine the new distance and the new mass of one object.

Given that the distance between the objects is reduced to 1/3rd of the original distance, the new distance would be r/3.
Given that the mass of one object is doubled, the new mass would be 2 * m1.

Using these values, the new gravitational force (F') can be calculated as follows:

F' = (G * (2 * m1) * m2) / (r/3)^2

Substituting the given values:

F' = (G * (2 * 10 kg) * 10 kg) / (r/3)^2

Now, we can simplify the equation:

F' = (G * 20 kg * 10 kg) / (r/3)^2

To determine the new gravitational force, we need to know the value of the gravitational constant G. However, since this value is not provided in the question, we cannot calculate the exact value of the new gravitational force.