Let the molecular mass of the gas be M.
The rate of diffusion of a gas is inversely proportional to the square root of its molecular mass.
Therefore, the rate of diffusion of the gas = 1/sqrt(M)
Given that the gas diffuses at a rate one half as fast as oxygen, we have:
(1/sqrt(M))/(1/sqrt(32)) = 1/2
sqrt(32)/sqrt(M) = 1/2
sqrt(32) = sqrt(M)*2
M = (sqrt(32))^2
M = 32
Therefore, the molecular mass of the gas is 32.
If the gas diffuse at a rate of one half as faster as oxygen, find the molecular mass of the gas?
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