If the first term of an arithmetic sequence is 10 and the 13th term is 58, what is the common difference?

Answer 1

The nth term of an arithmetic progression is defined by
n = a + (n-1)d where,
n = the nth term
a = the first term
d = the common difference

Therefore,
58 = 10 + (13 - 1)d
48 = 12d
d = 4

Answer 2

Find the 53rd term of the arithmetic sequence -12,-1,10