If the father's age in 3 years will be twice the son's age 4 years ago, and if the sum of their ages now is 106, how old is the father now?

Answer 1

f+s = 106
f+3 = 2(s-4)

now crank it out.

Answer 2

37

Answer 3

37

Answer 4

67

Answer 5

The correct answer is 67.

Here's how to solve it:

Let's use f for the father's age and s for the son's age.

From the first condition:

f + 3 = 2(s-4)

Simplifying this:

f + 3 = 2s - 8

f = 2s - 11

From the second condition:

f + s = 106

Substitute the first equation into the second:

(2s - 11) + s = 106

3s - 11 = 106

3s = 117

s = 39

Now we can use either of the two equations to find f:

f + 39 = 106

f = 67

So the father is currently 67 years old.