To simplify the expression \( 7^{15} \) using the Power Rule of Exponents, we know that \( a^{m \cdot n} = (a^m)^n \).
To find an expanded equivalent expression for \( 7^{15} \), we can express it as a product of smaller exponential components. The most straightforward way is to express it as \( (7^{5})^3 \), since \( 15 = 5 \times 3 \).
Now, checking the given options to find an equivalent expression:
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Option 1: \( (7^{10})^{5} \)
- This expands to \( 7^{10 \cdot 5} = 7^{50} \). Not equivalent.
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Option 2: \( (7 \cdot 7 \cdot 7 \cdot 7 \cdot 7)^{10} \)
- This simplifies to \( (7^5)^{10} = 7^{5 \cdot 10} = 7^{50} \). Not equivalent.
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Option 3: \( (7 \cdot 7 \cdot 7) \cdot (7 \cdot 7 \cdot 7) \cdot (7 \cdot 7 \cdot 7) \cdot (7 \cdot 7 \cdot 7) \cdot (7 \cdot 7 \cdot 7) \)
- This is equivalent to \( 7^3 \cdot 7^3 \cdot 7^3 \cdot 7^3 \cdot 7^3 = 7^{3 \cdot 5} = 7^{15} \). This is equivalent!
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Option 4: \( (7^{18})^{3} \)
- This expands to \( 7^{18 \cdot 3} = 7^{54} \). Not equivalent.
The correct answer is Option 3, which is the only expanded form equivalent to \( 7^{15} \).