If the expression 7^15 was simplified using the Power Rule of Exponents, which of the following would be an expanded equivalent expression? (1 point)

Responses

(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)

(7^18)^3

(7^10)^5

(7⋅7⋅7⋅7⋅7)^10

1 answer

To determine which of the given options is an expanded equivalent expression for \( 7^{15} \) using the Power Rule of Exponents, we need to break down the expression \( 7^{15} \) into a form that clearly shows multiplication of the base (7) a total of 15 times.

  1. The expression \((7 \cdot 7 \cdot 7) \cdot (7 \cdot 7 \cdot 7) \cdot (7 \cdot 7 \cdot 7) \cdot (7 \cdot 7 \cdot 7) \cdot (7 \cdot 7 \cdot 7)\) has 5 groups of 3 sevens each (which equals 15). So, this simplifies to \( 7^{15} \).

  2. The expression \((7^{18})^3\) would equal \( 7^{54} \), which is not equivalent to \( 7^{15} \).

  3. The expression \((7^{10})^5\) would equal \( 7^{50} \), which is not equivalent to \( 7^{15} \).

  4. The expression \((7 \cdot 7 \cdot 7 \cdot 7 \cdot 7)^{10}\) has 5 sevens multiplied together, which equals \( 7^5 \). When raised to the power of 10, that becomes \( 7^{50} \), which is not equivalent to \( 7^{15} \).

Considering the above options, the correct answer is:

(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)⋅(7⋅7⋅7)