dG = -RTlnK
nFE = RTlnK
If the equilibrium constant for a one-electron redox reaction at 298 K is 7.8 104, calculate the corresponding ÄG° and E°cell.
how would i set this problem up?
2 answers
G = -(8.314)(298)ln8.7x10^4=
-(-28179 J)/96485=
0.29 V
-(-28179 J)/96485=
0.29 V