The equation you provided is in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. In your equation \( y = 0.14x + 3 \), the slope \( m \) is \( 0.14 \) and the y-intercept \( b \) is \( 3 \).
If you change the y-intercept from \( 3 \) to \( 0 \), the new equation would be:
\[ y = 0.14x + 0 \]
This simplifies to:
\[ y = 0.14x \]
Changes to the Graph:
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Y-Intercept Shift: The original graph crosses the y-axis at the point \( (0, 3) \). After changing the y-intercept to \( 0 \), the new graph will cross the y-axis at the point \( (0, 0) \).
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Slope: The slope \( 0.14 \) remains the same, meaning the steepness and direction of the line (a positive slope that rises as it moves to the right) will not change.
Conclusion:
The graph will essentially shift downward by 3 units on the y-axis, moving the point where the line crosses the y-axis from \( (0, 3) \) to \( (0, 0) \). The overall orientation and slope of the line remain unchanged.