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If the driver of a car wishes to increase his speed from 20 mph to 50 mph while traveling a distance of 528 ft., what constant...Asked by justine
If the driver of a car wishes to increase his speed from 20 mph to 50 mph while traveling a distance of 528 ft., what constant acceleration should he maintain?
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Answered by
Henry
Vo = 20mi/h * 5280Ft/mi * 1h/3600s. =
29.3 Ft/s. = Initial velocity.
V = (50/20) * 29.3 = 73.3 Ft/s.
V^2 = Vo^2 + 2a*d.
Solve for a, Ft/s^2.
29.3 Ft/s. = Initial velocity.
V = (50/20) * 29.3 = 73.3 Ft/s.
V^2 = Vo^2 + 2a*d.
Solve for a, Ft/s^2.
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