The equation of a line whose center is (a, b) and radius is c is:
(x-a)^2 + (y-a)^2 = c^2
If the coordinates of the center of a circle are (-3,1) and the radius is 4, what is an equation of the circle
4 answers
Is it (x-3)^2 + (y-1)^2 =16
No, it's:
(x+3)^2 + (y-1)^2 = 16
(x+3)^2 + (y-1)^2 = 16
Thank you