if the concentration of all the reactants doubled, what works happen to the rate

Question

I know the reaction rate would increase, but in a previous example it asked the question and the answer was that the rate increases by 16 and I can't figure out how much it would increase for this question

The rate law expression for this question is R = K [ A ] ^ 1 [ B ] ^ 1

Answer 1

You plug the numbers into the rate expression.
rate = k*A*B
If you double A and double B then rate goes up by 4. Or the longer way is to make up a number for k, A and B. Let's make them easy and call k = 1, A = 2 and B = 3 so rate1 = 1*2*3 = 6
Now lets double A and double B so
rate = 1*4*6 = 24. Did the rate change by a factor of 4? yes, from 6 to 24 which is 4x more.