If the coefficient 2 is placed in front of the product tetraiodine nonaoxide (I4O9), then, how many atoms of each element must be accounted for on the otherside of the equation?

Question

A.
8 iodine atoms and 18 oxygen atoms
B.
4 iodine atoms and 9 oxygen atoms
C.
8 iodine atoms and 9 oxygen atoms
D.
9 iodine atoms and 4 oxygen atoms
E.
18 iodine atoms and 9 oxygen atoms

Answer 1

When you place the coefficient 2 in front of tetraiodine nonaoxide (I₄O₉), you effectively double the number of atoms of each element in the formula. Let's break it down:

The formula I₄O₉ indicates there are:

• 4 iodine atoms (I)
• 9 oxygen atoms (O)

When you place the coefficient 2 in front of I₄O₉, the new counts will be:

• Iodine atoms: 2 × 4 = 8
• Oxygen atoms: 2 × 9 = 18

So, the total count after adding the coefficient is:

• 8 iodine atoms and 18 oxygen atoms.

Therefore, the correct answer is: A. 8 iodine atoms and 18 oxygen atoms.