Asked by George
If the car has a mass of 0.4 kg, the ratio of height to width of the ramp is 13/125, the initial displacement is 1.9 m, and the change in momentum is 0.87 kg*m/s, how far will it coast back up the ramp before changing directions?
tinypic(dot)com(slant)r(slant)10dunx3/7
I get .3797m, but apparently this is not the right answer :( Could you please show the steps? I am have a quiz on this material coming up and would like an explanation on how to do this problem.
Thank you very much!
tinypic(dot)com(slant)r(slant)10dunx3/7
I get .3797m, but apparently this is not the right answer :( Could you please show the steps? I am have a quiz on this material coming up and would like an explanation on how to do this problem.
Thank you very much!
Answers
Answered by
drwls
Why should it coast back up the ramp at all? All that I see at the bottom of the ramp is a "force transducer".
http://tinypic.com/view.php?pic=10dunx3&s=7
Is y/x = 13/125 ?
I would not call the 125 a width.
How is the initial displacement defined?
http://tinypic.com/view.php?pic=10dunx3&s=7
Is y/x = 13/125 ?
I would not call the 125 a width.
How is the initial displacement defined?
Answered by
George
I know this seems like a silly question but our professor said we should be getting a very small value that will not even make a substantial difference. It is a poorly thought out problem. Yes y/x = 13/125. That's all I can really help with. Sorry :( Thank you for your help anyways though!
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