Asked by chemdumby

If the average quarter weighs 5.67grams, how many atoms of nickel are in a quarter?

ie; 91.67%mass/copper 8.33%mass/nickel

I took 5.67x0.0833=.47g
.47gNi/58.6934=801 atoms nickel? is this right?
Answered by DrBob222
5.67 x 0.0833 = 0.47 g Ni is correct but you rounded too much. You are allowed three significant figures so I would use all of them and I get 0.472.
Then 0.472gNi/58.693 = 0.00804 is the right process but that added two on mine makes my answer a little higher. This is the right number but it is the number of MOLES Ni, not atoms.
Now remember that there are 6.022E23 atoms in a mole of Ni so
0.00804 x 6.22E23 = # atoms Ni.
Answered by Bob
Why 58.693
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