If the arc of a circle is 15 meters long and the radius of the circle is 3 meters, then what is the measure of the central angle, to the nearest tenth of a degree, that intercepts that 15-meter arc?(1 point)

Responses

282.7 degrees
282.7 degrees

7.9 degrees
7.9 degrees

353.4 degrees
353.4 degrees

286.5 degrees

1 answer

To find the measure of the central angle that intercepts a given arc, you can use the formula:

\[ \text{Arc Length} = r \cdot \theta \]

where:

  • \(\text{Arc Length}\) is the length of the arc,
  • \(r\) is the radius of the circle,
  • \(\theta\) is the central angle in radians.

In this case, the arc length is 15 meters and the radius \(r\) is 3 meters. We need to solve for \(\theta\):

\[ 15 = 3 \cdot \theta \]

Dividing both sides by 3 gives:

\[ \theta = \frac{15}{3} = 5 \text{ radians} \]

Next, we need to convert \(\theta\) from radians to degrees. The conversion factor is:

\[ 180^\circ = \pi \text{ radians} \]

Thus:

\[ \theta \text{ in degrees} = \theta \text{ in radians} \cdot \frac{180^\circ}{\pi} \]

Substituting in our value for \(\theta\):

\[ \theta \text{ in degrees} = 5 \cdot \frac{180^\circ}{\pi} \approx 5 \cdot 57.2958 \approx 286.5^\circ \]

So the central angle that intercepts the 15-meter arc is approximately \(286.5\) degrees.

The correct response is:

286.5 degrees