To determine the number of 4 oz bottles the solution would fill if the amount of Chlorpheniramine was doubled, we need to know the total volume of the solution.
If we assume that the volume of the solution remains constant, we can use the following proportion:
Amount of Chlorpheniramine 1 / Volume 1 = Amount of Chlorpheniramine 2 / Volume 2
Let's say there are x 4 oz bottles in Volume 1 (original solution).
1 oz = 4/4 = 4/4 oz = 1 bottle
Therefore, Volume 1 would be x * 4 oz.
If the amount of Chlorpheniramine is doubled, the Amount of Chlorpheniramine 2 would be 2 times the Amount of Chlorpheniramine 1. Again, assuming volume 2 is the same as volume 1, we have:
2 * Amount of Chlorpheniramine 1 = Amount of Chlorpheniramine 2
Let's say the Amount of Chlorpheniramine 1 is C.
2C = Amount of Chlorpheniramine 2
Now we can set up the proportion:
C / (x * 4) oz = (2C) / (x * 4) oz
Simplifying the equation:
C * x * 4 = 2C * x * 4
Dividing both sides by 4:
C * x = 2C * x
Cancelling out the C:
x = 2 * x
As the equation implies that the number of 4 oz bottles (x) is equal to 2 times the number of 4 oz bottles (x), it is not possible to determine a single value for the number of bottles since they would be infinite.
Therefore, if the amount of Chlorpheniramine was doubled, the solution would not change the number of 4 oz bottles it would fill, assuming the volume remains constant.
If the amount of Chlorpheniramine was doubled, how many 4 oz bottles would the solution fill?
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