2θ is in QIV, so θ is in QII, and we have
y = -24
x = 7
r = 25
sin2θ = y/r = -24/25
cos2θ = /r = 7/25
now just apply the half-angle formulas and the identity should fall right out
If tan 2x = - 24/7, where 90 degrees < x < 180 degrees, then find the value of sin x+ cos x.
I applied various identities and tried manipulating the problem to get sin x + cos x = sin(arctan(-24/7)/2) + cos(arctan(-24/7)/2)
I also played around with the half-angle formula and the double angle formula but they both don't seem to work. Help would be appreciated, thanks.
2 answers
Thanksa lot