(a) The relationship between T and s can be expressed as T = k/s, where k is a constant.
(b) If T varies inversely with s, then T = k/s. To find the value of T when s = 90, we can use the given information T = 2 and s = 60 to solve for k.
2 = k/60
Multiply both sides of the equation by 60:
120 = k
Now we can substitute this value of k into our equation to find T when s = 90:
T = (120)/90
T = 4/3
Therefore, when s = 90, T = 4/3.
(c) To find the value of s when T = 5/2, we can again use the equation T = k/s, and substitute T = 5/2 into the equation:
5/2 = k/s
Multiply both sides of the equation by s:
(5/2)s = k
Now we can substitute this value of k into our equation, along with T = 2, to solve for s:
2 = (5/2)s/s
2 = (5/2)
Multiply both sides of the equation by 2:
4 = 5s
Divide both sides of the equation by 5:
s = 4/5
Therefore, when T = 5/2, s = 4/5.
if T varries inversly as s . T=2 and s=60, find (a) the relatinship between T and s (b) find the value of T when s=90 (c) find s when T=5/2
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