If T=2π√L/8 Then given that L=100.0±0.1cm(limit standard errors) and T=2.01±0.01s(limit standard error) Calculate the value of g and its standard error

Answer 1

I think you mean T=2π√(L/g)
Use metric units, L = 1.000 + 0.001, T = 2.01 - 0.01
let me see:
T^2 /(2 pi)^2 = L/g
g = L (2 pi)^2/T^2
calculate that for L = 1, T = 2.01
and for L = 1.001 and T = 2.00