if sin23=p,write down the following in terms of P

*cos113
*cos23
*sin46
so i draw the diagram an solve for x in terms of P an got 1-p
so i don't know how to apply cos113and sin46 in terms of 23 or P
but *cos 23 i wrote it as> 1-p/1 wch is 1-p

1 answer

since sin^2 + cos^2 = 1,
cos(23) = āˆš(1-p^2)

cos(113) = cos(23+90) = cos(23)cos(90) - sin(23)sin(90) = -p

sin(46) = 2sin(23)cos(23) = 2pāˆš(1-p^2)

Time to review your basic sum/double-angle formulas