tan = sin / cos
cos = √(1 - sin^2)
tan = sin / √(1 - sin^2) = (3/4) / √[1 - (3/4)^2]
if sin p = 3/4 and p is an acute angle, what is the value of tan p
2 answers
draw a right triangle with the side opposite P = 3 and the hypotenuse = 4
Then the remaining side is √(4^2 - 3^2) = √7
so tan p = 3/√7
Then the remaining side is √(4^2 - 3^2) = √7
so tan p = 3/√7