If sin A=0.31, cos A=0.95, sin B=0.47, and cos B=0.88, what is sin(A+B)

Answer 1

To find sin(A + B), we can use the sine addition formula:

sin(A + B) = sin A * cos B + cos A * sin B

Plugging in the values we have:

sin(A + B) = (0.31)(0.88) + (0.95)(0.47)
sin(A + B) = 0.2728 + 0.4465
sin(A + B) = 0.7193

Therefore, sin(A + B) ≈ 0.7193.