If sec x = 17/8; verify that 3 - 4sin^2x /4cos^2x -3 = 3- tan^2x / 1-3tan^2x.. I have used x in place of theta. It isn't multiplication symbol.. ^2 means to the power 2. Pls help

Answer 1

secx = 17/8, so
cosx = 8/17
sinx = 15/17
tanx = 15/8

Now just plug in your values:

(3-4sin^2x)/(4cos^2x-3)
= (3-4(15/17)^2)/(4(8/17)^2-3)
= 33/611

(3-tan^2x)/(1-3tan^2x)
= (3-(15/8)^2)/(1-3(15/8)^2)
= 33/611