if sec tita is 5/4 verify tan tita/1 plus tan^2 tita= sin tita/cosec tita

Answer 1

If you can't spell theta you might as well just use x.

secθ = 5/4
so,
sinθ = 3/5
cscθ = 5/3
tanθ = 3/4

tanθ/(1+tan^2θ) = sinθ/cscθ
(3/4)/(1+9/16) = (3/5)/(5/3)
(3/4)/(25/16) = 9/25
3/4 * 16/25 = 9/25
12/25 = 9/25
Hmmm. I suspect a flaw in the equation.

Answer 2

So, is it ever true?

tanθ/(1+tan^2θ) = sinθ/cscθ
tanθ/sec^2θ = sin^2θ
sinθ cosθ = sin^2θ
sinθ(cosθ-sinθ) = 0
θ = π/4

Answer 3

if cot x is 3/4 prove that root of sec x-cosec x/ sec x plus cosec x= 1/root 7

Answer 4

if cot x = 3/4
sec x = 5/3
csc x = 5/4

So, plug in the values and see whether it's true.