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If RS is a midsegment of triangle HIT and parallel to side HI, and RS is 2x + 6 and HI is 5x + 9, write and solve an equation to find the lengths of the segments.

How do I go about doing this?

3 answers

If RS is a midsegment, then it is half as long as the parallel side. So,

2(2x+6) = 5x+9

Solve for x, and then you can figure the lengths.

2(2x+6) = 5x+9 or 2x+6 = 5x+9?

RS is half as long as HI ...

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