If RS is a midsegment, then it is half as long as the parallel side. So,
2(2x+6) = 5x+9
Solve for x, and then you can figure the lengths.
If RS is a midsegment of triangle HIT and parallel to side HI, and RS is 2x + 6 and HI is 5x + 9, write and solve an equation to find the lengths of the segments.
How do I go about doing this?
3 answers
2(2x+6) = 5x+9 or 2x+6 = 5x+9?
RS is half as long as HI ...