If R, S, equals, 62RS=62, S, Q, equals, 64SQ=64, R, Q, equals, 76RQ=76, V, T, equals, 32VT=32, and U, T, equals, 38UT=38, find the perimeter of triangle, T, U, V△TUV. Round your answer to the nearest tenth if necessary. Figures are not necessarily drawn to scale

Answer 1

To find the perimeter of triangle TUV, we need to find the lengths of all three sides and then add them together.

From the given information, we know the following:
UT = 38
VT = 32

To find TU, we can use the Pythagorean theorem because triangle TUV is a right triangle.
Let UT = x, VT = y, and TU = z.
We have:
x^2 + y^2 = z^2
38^2 + 32^2 = z^2
1444 + 1024 = z^2
2468 = z^2
z ≈ 49.7

Therefore, the lengths of the sides of triangle TUV are:
UT = 38
VT = 32
TU = z ≈ 49.7

The perimeter of triangle TUV is:
38 + 32 + 49.7 ≈ 119.7

Therefore, the perimeter of triangle TUV is approximately 119.7.