In a parallelogram, opposite sides are congruent. Since \( VSTU \) is a parallelogram, the side opposite \( VE \) must be congruent to \( VE \).
To determine which segment is congruent to \( VE \), we first need to identify where point \( E \) is located in relation to the vertices of the parallelogram \( VSTU \). Assuming the points \( V \), \( S \), \( T \), and \( U \) correspond with some order and understanding that:
- \( VS \) is opposite \( TU \)
- \( VT \) is opposite \( SU \)
If we consider \( VE \) as a segment within the parallelogram, then the segment that corresponds in terms of congruence would also be \( SE \).
Thus, the segment that must be congruent to \( VE \) is:
SE.