If PRQ has <P=30 and <R=127 and FGH has <H=30 and <G=23, what criterion has been met to prove the triangles similar?

SSS
ASA
SAS
AA

1 answer

To determine the criterion for similarity between the triangles PRQ and FGH using the given angle measurements, we can analyze the information as follows:

For triangle PRQ:

  • Angle P = 30°
  • Angle R = 127°

To find angle Q, we can use the fact that the sum of the angles in a triangle is 180°: \[ \angle Q = 180° - \angle P - \angle R = 180° - 30° - 127° = 23° \]

So the angles in triangle PRQ are:

  • Angle P = 30°
  • Angle R = 127°
  • Angle Q = 23°

For triangle FGH:

  • Angle H = 30°
  • Angle G = 23°

To find angle F, we again use the sum of the angles in a triangle: \[ \angle F = 180° - \angle H - \angle G = 180° - 30° - 23° = 127° \]

So the angles in triangle FGH are:

  • Angle H = 30°
  • Angle G = 23°
  • Angle F = 127°

Now, we can compare the angles of both triangles:

  • Triangle PRQ: 30°, 127°, 23°
  • Triangle FGH: 30°, 23°, 127°

We see that both triangles have two pairs of corresponding angles that are equal:

  • \(\angle P\) (30°) corresponds to \(\angle H\) (30°)
  • \(\angle Q\) (23°) corresponds to \(\angle G\) (23°)
  • \(\angle R\) (127°) corresponds to \(\angle F\) (127°)

Since two angles in each triangle are equal, we can conclude that the triangles are similar by the Angle-Angle (AA) criterion.

Therefore, the criterion that has been met to prove the triangles PRQ and FGH similar is AA (Angle-Angle).