To determine if triangles ΔPRQ and ΔFGH are similar, we look at the angles given:
-
In ΔPRQ:
- ∠P = 30°
- ∠R = 127°
- To find ∠Q: \[ ∠Q = 180° - (30° + 127°) = 180° - 157° = 23° \]
-
In ΔFGH:
- ∠H = 30°
- ∠G = 23°
- To find ∠F: \[ ∠F = 180° - (30° + 23°) = 180° - 53° = 127° \]
Now we have:
- ΔPRQ: ∠P = 30°, ∠R = 127°, ∠Q = 23°
- ΔFGH: ∠H = 30°, ∠G = 23°, ∠F = 127°
Both triangles have the same set of angles:
- ∠P = ∠H = 30°
- ∠Q = ∠G = 23°
- ∠R = ∠F = 127°
Since both triangles have two pairs of equal angles, we can use the Angle-Angle (AA) criterion for triangle similarity.
Thus, the criterion that has been met to prove the triangles similar is AA.