To determine if the triangles ΔPRQ and ΔFGH are similar, we need to analyze the angles given.
In ΔPRQ:
- ∠P = 30°
- ∠R = 127°
To find ∠Q, we can use the fact that the sum of the angles in a triangle is 180°:
∠Q = 180° - (∠P + ∠R) ∠Q = 180° - (30° + 127°) = 180° - 157° = 23°
In ΔFGH:
- ∠H = 30°
- ∠G = 23°
To find ∠F, we also use the same principle:
∠F = 180° - (∠H + ∠G) ∠F = 180° - (30° + 23°) = 180° - 53° = 127°
Now we have the angles:
- In ΔPRQ: ∠P = 30°, ∠R = 127°, ∠Q = 23°
- In ΔFGH: ∠H = 30°, ∠G = 23°, ∠F = 127°
Comparing the angles:
- ∠P = ∠H = 30°
- ∠R = ∠F = 127°
- ∠Q = ∠G = 23°
Since two triangles have two pairs of corresponding angles equal, they are similar by the AA (Angle-Angle) criterion.
Therefore, the correct answer is AA.