If p varies directly as the cube of x and p=27,when x=3 find p when x=2

Answer 1

If p varies directly as the cube of x, we can write the equation as p = kx³, where k is the constant of variation.

Given that p = 27 when x = 3, we can substitute these values into the equation and solve for k:

27 = k(3)³
27 = k(27)
k = 1

Now we can use the value of k to find p when x = 2:

p = 1(2)³
p = 1(8)
p = 8

Therefore, when x = 2, p = 8.