If only one-eighth of the sodium-24 remains, roughly how many hours have elapsed, given its half-life is approximately 15 hours?/

1 answer

To determine how many hours have elapsed when only one-eighth of sodium-24 remains, we can use the concept of half-lives.

The half-life of sodium-24 is 15 hours. This means that every 15 hours, half of the remaining sodium-24 decays.

To find out how many half-lives it takes to go from a full amount to one-eighth, we can analyze the situation:

  • After 1 half-life (15 hours), \( \frac{1}{2} \) of the original amount remains.
  • After 2 half-lives (30 hours), \( \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \) remains.
  • After 3 half-lives (45 hours), \( \frac{1}{4} \times \frac{1}{2} = \frac{1}{8} \) remains.

Since it takes 3 half-lives to reach one-eighth of the original amount, we can calculate the total elapsed time:

\[ 3 \text{ half-lives} \times 15 \text{ hours/half-life} = 45 \text{ hours} \]

Therefore, approximately 45 hours have elapsed.