If one zero of polynomial (a^2+a)x^2+13x+6a is reciprocal of other ,find a.

Answer 1

well, the product of the roots is

(6a)/(a^2+a) = 1
6a = a^2+a
a^2-5a = 0
a(a-5) = 0
a=5

30x^2+13x+30
has roots (-13±√3431 i)/60

which are reciprocals

Answer 2

I don't understand please do it again.....♥