Asked by shehzad
if one side of a square is increased by 2metres and other side is reduced by 2 metres. a rectangle is formed whose perimeter is 48.find the side of the orignal square.
Answers
Answered by
Justin
If you reduce one side by the same amount of what you increase on another side, the differences should cancel out. Thus the perimeter should stay the same, easily leaving 48(Perimeter of your rectangle AND square) to be divided by 4 (sides of a square).
Answered by
Reiny
proof of what Justin said:
let sides of original square be x by x
perimeter = 4x
new length = x+3
new width = x-3
new perimeter = 2(x+3) + 2(x-3)
= 2x + 6 + 2x - 6
= 4x , just as before
so original side = 84/4 = 21
let sides of original square be x by x
perimeter = 4x
new length = x+3
new width = x-3
new perimeter = 2(x+3) + 2(x-3)
= 2x + 6 + 2x - 6
= 4x , just as before
so original side = 84/4 = 21
Answered by
histy
uajsi123
23123
2312
321
3312
32
123
123
12
3
23123
2312
321
3312
32
123
123
12
3
There are no AI answers yet. The ability to request AI answers is coming soon!