if one side of a square is increased by 2metres and other side is reduced by 2 metres. a rectangle is formed whose perimeter is 48.find the side of the orignal square.

Answer 1

If you reduce one side by the same amount of what you increase on another side, the differences should cancel out. Thus the perimeter should stay the same, easily leaving 48(Perimeter of your rectangle AND square) to be divided by 4 (sides of a square).

Answer 2

proof of what Justin said:

let sides of original square be x by x
perimeter = 4x

new length = x+3
new width = x-3
new perimeter = 2(x+3) + 2(x-3)
= 2x + 6 + 2x - 6
= 4x , just as before

so original side = 84/4 = 21

Answer 3

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