if [OH^-]=10^-pOH. NAd the pOH=7.85 then what does [OH^-]equal?

Question

DrBob222 · Answer

pOH = 7.85
- log(OH^-) = 7.85
(OH^-) = 1.41 x 10^-8
Do you know how to do this on your calculator. Enter 7.85 on the calculator, hit the change sign (or if your calculator doesn't have a changr sign, enter -7.85), then hit the 10^x button.

Hillary · Answer

thank you so much you simplified it for me perfectly.

if [OH-]=10-pOH. NAd the pOH=7.85 then what does [OH-]equal?

if [OH^-]=10^-pOH. NAd the pOH=7.85 then what does [OH^-]equal?