IF NO DIGIT MAY BE USED MORE THAN ONCE, HOW MANY 2-DIGIT NUMBERS CAN BE FORMED USING ONLY THE DIGITS 9, 6, 5, 7, 4, AND 2?

Answer 1

There are six choices for the first digit (any of the six given digits can be used), and five choices for the second digit (only five digits are left after choosing the first). Therefore, there are $6\times5=\boxed{30}$ 2-digit numbers that can be formed using only the digits $9, 6, 5, 7, 4,$ and $2$, with no digit used more than once.

Answer 2

so how many?

Answer 3

There are $\boxed{30}$ possible 2-digit numbers that can be formed using only the digits 9, 6, 5, 7, 4, and 2, with no digit used more than once.