well, n^2-n = n(n-1) which is even
the p^2-q^2 is odd-odd which is also even
so 2 is clearly a common factor
if n is a positive integer greater than 2 and p and q are prime numbers greater than 6 then what is common factor of n^2-n and p^2-q^2???
3 answers
@oobleck
Answer is 7
Answer is 7
huh? Suppose n=3. 3^2-3 = 6
and suppose p and q are 11 and 7. 11^2-6^2 = 72
I don' see no steenking 7s in thos numbers.
and suppose p and q are 11 and 7. 11^2-6^2 = 72
I don' see no steenking 7s in thos numbers.