If n=-8, what is the smallest perfect square that is greater than n^2 ?

Question

a. 64
b. -64
c. 81
d. -81
e. 16

please answer and explain

Answer 1

81 > n^2 = (-8)^2

Answer 2

a. 64

Answer 3

i use (-8)x (-8) = 64

I use calculator X^2

-8^2 = -64

Answer 4

However, they are asking for the smallest square greater than 64, which is 81.

Note that
-8^2 = -(8^2) = -64
(-8)^2 = +64