If n+1 is the largest of four consecutuve integers, represent the sum of four integers.

Question

A 4n+10
B 4n-2
C 4n-4
D 4n-5
E 4n-8

I really don`t understand this question so I can`t provide my work. Can someone please explain to me how to solve these types of problems. Thank you

Answer 1

sum = = m + m+1 + m+2 + m+3

but n+1 = m+3
so m = n-2

sum = 4 m + 6 = 4(n-2)+3
=4 n -8+3
= 4 n - 5

Answer 2

i think
n - 2 + n - 1 + n + n + 1, thereby
4n - 2