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If my question is 1x (x = 17) + 40 and my other is 1x (x = 25) how long does it take to equal the same amount?

3 answers

To solve the problem, let's first evaluate each expression separately.

  1. For the first expression:
    \( 1x + 40 \) with \( x = 17 \)
    Substitute \( x \) into the equation:
    \( 1(17) + 40 = 17 + 40 = 57 \)

  2. For the second expression:
    \( 1x \) with \( x = 25 \)
    \( 1(25) = 25 \)

Now, you want to know how long it takes for these two expressions to equal the same amount.

Let’s set both expressions equal to each other and solve for \( x \):

\[ 1x + 40 = 1x \]

However, since \( 1x \) does not depend on \( x \) in a way that allows direct equality with random constants like 40 and changes with \( x \), they can’t be equal unless you add a variable or equation that needs solving.

If you intended to determine when changes in these expressions equal either of the results, we would need a clearer context or another condition to evaluate.

Please clarify your question if there's more detail or a different context involved!

Each time you add like 2 and it gets like to 50 and 2 = 74 what time will they both equal the same amount

From your follow-up, it sounds like you're defining a scenario where each expression increases by a constant amount over time. Let's explore that.

Given Expressions:

  1. The first expression starts at \( 57 \) (from \( 1x + 40 \) where \( x = 17 \)) and increases by \( 2 \) each time.

    • Expression: \( 57 + 2t \) (where \( t \) is the number of times you add \( 2 \))

  2. The second expression starts at \( 25 \) (from \( 1x \) where \( x = 25 \)) and also increases by \( 2 \) each time.

    • Expression: \( 25 + 2t \)

Setting the Two Expressions Equal:

To find out when both expressions equal each other: \[ 57 + 2t = 25 + 2t \]

Simplifying:

If we subtract \( 2t \) from both sides: \[ 57 = 25 \]

This statement is not true, meaning the two expressions \( 57 + 2t \) and \( 25 + 2t \) will never be equal no matter how many times you add \( 2 \), because you have established that both expressions start from different initial points that will forever remain apart.

Conclusion:

In this case, there is no time \( t \) when both expressions will equal the same amount since the starting parameters are different and the increase is identical.

Could you please clarify or provide more context if there are specifics you wish to explore further?