a. V^2 = Vo^2 + 2g*h = 0
Vo^2 = -2g*h = -(-19.6)*1.29 = 25.284
Vo = 5.03 m/s
b. 0.5g*t^2 = 1.29 m.
4.9t^2 = 1.29
t^2 = 0.263
Tf = 0.513 s. = Fall Time.
Tr = Tf = 0.513 s. = Rise time.
Hang time = Tr + Tf = 0.513 + 0.513 = 1.026 s.
If micheal Jordan has a vertical leap of 1.29 m, what is his take off speed and his hang time(total time to move upwards to the peak and then return to the ground)?
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